Base | Representation |
---|---|
bin | 11110101010100101100… |
… | …00100110111000011111 |
3 | 10201201200001122021110102 |
4 | 33111102300212320133 |
5 | 114230341244231112 |
6 | 2124013113131315 |
7 | 136060364435453 |
oct | 17252260467037 |
9 | 3651601567412 |
10 | 1053655461407 |
11 | 37694204822a |
12 | 1502570b9b3b |
13 | 78489466883 |
14 | 38dd6442663 |
15 | 1c61bec5bc2 |
hex | f552c26e1f |
1053655461407 has 2 divisors, whose sum is σ = 1053655461408. Its totient is φ = 1053655461406.
The previous prime is 1053655461403. The next prime is 1053655461427. The reversal of 1053655461407 is 7041645563501.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (7041645563501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1053655461407 - 22 = 1053655461403 is a prime.
It is a super-2 number, since 2×10536554614072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1053655461403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526827730703 + 526827730704.
It is an arithmetic number, because the mean of its divisors is an integer number (526827730704).
Almost surely, 21053655461407 is an apocalyptic number.
1053655461407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053655461407 is an equidigital number, since it uses as much as digits as its factorization.
1053655461407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512000, while the sum is 47.
The spelling of 1053655461407 in words is "one trillion, fifty-three billion, six hundred fifty-five million, four hundred sixty-one thousand, four hundred seven".
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