Base | Representation |
---|---|
bin | 110001001001010110… |
… | …0010011010011100111 |
3 | 101002102021200211220010 |
4 | 1202102230103103213 |
5 | 3212121304131210 |
6 | 120252354541303 |
7 | 10424246523426 |
oct | 1422254232347 |
9 | 332367624803 |
10 | 105540302055 |
11 | 40839827031 |
12 | 18555297833 |
13 | 9c4c594596 |
14 | 5172ba92bd |
15 | 2b2a81a920 |
hex | 1892b134e7 |
105540302055 has 32 divisors (see below), whose sum is σ = 177041640960. Its totient is φ = 53585642880.
The previous prime is 105540301991. The next prime is 105540302113. The reversal of 105540302055 is 550203045501.
It is a happy number.
It is not a de Polignac number, because 105540302055 - 26 = 105540301991 is a prime.
It is a super-3 number, since 3×1055403020553 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 652120 + ... + 797709.
It is an arithmetic number, because the mean of its divisors is an integer number (5532551280).
Almost surely, 2105540302055 is an apocalyptic number.
105540302055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
105540302055 is a deficient number, since it is larger than the sum of its proper divisors (71501338905).
105540302055 is a wasteful number, since it uses less digits than its factorization.
105540302055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1450071.
The product of its (nonzero) digits is 15000, while the sum is 30.
Adding to 105540302055 its reverse (550203045501), we get a palindrome (655743347556).
The spelling of 105540302055 in words is "one hundred five billion, five hundred forty million, three hundred two thousand, fifty-five".
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