Base | Representation |
---|---|
bin | 1001101011100001011011… |
… | …0001111111111001001111 |
3 | 1101200111020122200110022002 |
4 | 2122320112301333321033 |
5 | 2343340000124240012 |
6 | 34345245235542515 |
7 | 2145645113126363 |
oct | 232702661777117 |
9 | 41614218613262 |
10 | 10643311165007 |
11 | 3433891755964 |
12 | 123a8b345aa3b |
13 | 5c2876b59501 |
14 | 28b1d36252a3 |
15 | 136ccc3037c2 |
hex | 9ae16c7fe4f |
10643311165007 has 2 divisors, whose sum is σ = 10643311165008. Its totient is φ = 10643311165006.
The previous prime is 10643311164991. The next prime is 10643311165009. The reversal of 10643311165007 is 70056111334601.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10643311165007 - 24 = 10643311164991 is a prime.
It is a super-2 number, since 2×106433111650072 (a number of 27 digits) contains 22 as substring.
Together with 10643311165009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10643311165009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321655582503 + 5321655582504.
It is an arithmetic number, because the mean of its divisors is an integer number (5321655582504).
Almost surely, 210643311165007 is an apocalyptic number.
10643311165007 is a deficient number, since it is larger than the sum of its proper divisors (1).
10643311165007 is an equidigital number, since it uses as much as digits as its factorization.
10643311165007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45360, while the sum is 38.
Adding to 10643311165007 its reverse (70056111334601), we get a palindrome (80699422499608).
The spelling of 10643311165007 in words is "ten trillion, six hundred forty-three billion, three hundred eleven million, one hundred sixty-five thousand, seven".
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