11000103231319 has 2 divisors, whose sum is σ = 11000103231320. Its totient is φ = 11000103231318.

The previous prime is 11000103231277. The next prime is 11000103231361. The reversal of 11000103231319 is 91313230100011.

It is a balanced prime because it is at equal distance from previous prime (11000103231277) and next prime (11000103231361).

It is an emirp because it is prime and its reverse (91313230100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000103231319 - 2²⁵ = 11000069676887 is a prime.

It is a super-2 number, since 2×11000103231319² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000103231293 and 11000103231302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000103231419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500051615659 + 5500051615660.

It is an arithmetic number, because the mean of its divisors is an integer number (5500051615660).

Almost surely, 2^{11000103231319} is an apocalyptic number.

11000103231319 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000103231319 is an equidigital number, since it uses as much as digits as its factorization.

11000103231319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 11000103231319 in words is "eleven trillion, one hundred three million, two hundred thirty-one thousand, three hundred nineteen".