Base | Representation |
---|---|
bin | 10100011111010100… |
… | …01010100111011100 |
3 | 1001101121200111120200 |
4 | 22033222022213130 |
5 | 140012013130022 |
6 | 5015310543500 |
7 | 536410363614 |
oct | 121752124734 |
9 | 31347614520 |
10 | 11000130012 |
11 | 4735317543 |
12 | 216bb07b90 |
13 | 1063c71891 |
14 | 764d05a44 |
15 | 445ab7bac |
hex | 28fa8a9dc |
11000130012 has 36 divisors (see below), whose sum is σ = 28764710520. Its totient is φ = 3540271392.
The previous prime is 11000129999. The next prime is 11000130017. The reversal of 11000130012 is 21003100011.
It is a tau number, because it is divible by the number of its divisors (36).
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 11000129976 and 11000130003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11000130017) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5267218 + ... + 5269305.
Almost surely, 211000130012 is an apocalyptic number.
11000130012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11000130012 is an abundant number, since it is smaller than the sum of its proper divisors (17764580508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11000130012 is a wasteful number, since it uses less digits than its factorization.
11000130012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10536562 (or 10536557 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
Adding to 11000130012 its reverse (21003100011), we get a palindrome (32003230023).
The spelling of 11000130012 in words is "eleven billion, one hundred thirty thousand, twelve".
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