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110002231310000 = 245429379318039
BaseRepresentation
bin11001000000101111100011…
…111010111111011010110000
3112102111002222122011002000012
4121000233203322333122300
5103404234032203410000
61025542154420314052
732112253560401531
oct3100574372773260
9472432878132005
10110002231310000
1132060758905447
1210407204842928
13494c220646133
141d241ca40c688
15cab625566735
hex640be3ebf6b0

110002231310000 has 100 divisors (see below), whose sum is σ = 275510071993200. Its totient is φ = 42483620256000.

The previous prime is 110002231309987. The next prime is 110002231310003. The reversal of 110002231310000 is 13132200011.

110002231310000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (100).

It is a super-2 number, since 2×1100022313100002 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (110002231310003) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 189369020 + ... + 189949019.

It is an arithmetic number, because the mean of its divisors is an integer number (2755100719932).

Almost surely, 2110002231310000 is an apocalyptic number.

110002231310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

110002231310000 is an abundant number, since it is smaller than the sum of its proper divisors (165507840683200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110002231310000 is an equidigital number, since it uses as much as digits as its factorization.

110002231310000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379318096 (or 379318075 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 110002231310000 its reverse (13132200011), we get a palindrome (110015363510011).

The spelling of 110002231310000 in words is "one hundred ten trillion, two billion, two hundred thirty-one million, three hundred ten thousand".

Divisors: 1 2 4 5 8 10 16 20 25 29 40 50 58 80 100 116 125 145 200 232 250 290 400 464 500 580 625 725 1000 1160 1250 1450 2000 2320 2500 2900 3625 5000 5800 7250 10000 11600 14500 18125 29000 36250 58000 72500 145000 290000 379318039 758636078 1517272156 1896590195 3034544312 3793180390 6069088624 7586360780 9482950975 11000223131 15172721560 18965901950 22000446262 30345443120 37931803900 44000892524 47414754875 55001115655 75863607800 88001785048 94829509750 110002231310 151727215600 176003570096 189659019500 220004462620 237073774375 275005578275 379318039000 440008925240 474147548750 550011156550 758636078000 880017850480 948295097500 1100022313100 1375027891375 1896590195000 2200044626200 2750055782750 3793180390000 4400089252400 5500111565500 6875139456875 11000223131000 13750278913750 22000446262000 27500557827500 55001115655000 110002231310000