11000425453 has 2 divisors, whose sum is σ = 11000425454. Its totient is φ = 11000425452.

The previous prime is 11000425393. The next prime is 11000425463. The reversal of 11000425453 is 35452400011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10948901769 + 51523684 = 104637^2 + 7178^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000425453 - 2¹³ = 11000417261 is a prime.

It is a super-3 number, since 3×11000425453³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000425463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500212726 + 5500212727.

It is an arithmetic number, because the mean of its divisors is an integer number (5500212727).

Almost surely, 2^11000425453 is an apocalyptic number.

It is an amenable number.

11000425453 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000425453 is an equidigital number, since it uses as much as digits as its factorization.

11000425453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 11000425453 its reverse (35452400011), we get a palindrome (46452825464).

The spelling of 11000425453 in words is "eleven billion, four hundred twenty-five thousand, four hundred fifty-three".