1100100101131 has 2 divisors, whose sum is σ = 1100100101132. Its totient is φ = 1100100101130.

The previous prime is 1100100101129. The next prime is 1100100101141. The reversal of 1100100101131 is 1311010010011.

It is an a-pointer prime, because the next prime (1100100101141) can be obtained adding 1100100101131 to its sum of digits (10).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100100101131 - 2¹ = 1100100101129 is a prime.

It is a super-2 number, since 2×1100100101131² (a number of 25 digits) contains 22 as substring.

Together with 1100100101129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1100100101141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050050565 + 550050050566.

It is an arithmetic number, because the mean of its divisors is an integer number (550050050566).

Almost surely, 2^{1100100101131} is an apocalyptic number.

1100100101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100100101131 is an equidigital number, since it uses as much as digits as its factorization.

1100100101131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 1100100101131 its reverse (1311010010011), we get a palindrome (2411110111142).

The spelling of 1100100101131 in words is "one trillion, one hundred billion, one hundred million, one hundred one thousand, one hundred thirty-one".