110011001009983 has 2 divisors, whose sum is σ = 110011001009984. Its totient is φ = 110011001009982.

The previous prime is 110011001009981. The next prime is 110011001010089. The reversal of 110011001009983 is 389900100110011.

It is a weak prime.

It is an emirp because it is prime and its reverse (389900100110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110011001009983 - 2¹ = 110011001009981 is a prime.

Together with 110011001009981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011001009981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005500504991 + 55005500504992.

It is an arithmetic number, because the mean of its divisors is an integer number (55005500504992).

Almost surely, 2^{110011001009983} is an apocalyptic number.

110011001009983 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011001009983 is an equidigital number, since it uses as much as digits as its factorization.

110011001009983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 34.

Adding to 110011001009983 its reverse (389900100110011), we get a palindrome (499911101119994).

The spelling of 110011001009983 in words is "one hundred ten trillion, eleven billion, one million, nine thousand, nine hundred eighty-three".