Base | Representation |
---|---|
bin | 11001000000110111111010… |
… | …100000010010010011010111 |
3 | 112102111222010200112211102012 |
4 | 121000313322200102103113 |
5 | 103404410414212320043 |
6 | 1025550240405134435 |
7 | 32113022044126646 |
oct | 3100677240222327 |
9 | 472458120484365 |
10 | 110011200120023 |
11 | 32064540533134 |
12 | 10408aa83ba41b |
13 | 495001c7c5907 |
14 | 1d247db62535d |
15 | cab99cb31a18 |
hex | 640dfa8124d7 |
110011200120023 has 2 divisors, whose sum is σ = 110011200120024. Its totient is φ = 110011200120022.
The previous prime is 110011200119999. The next prime is 110011200120037. The reversal of 110011200120023 is 320021002110011.
It is an a-pointer prime, because the next prime (110011200120037) can be obtained adding 110011200120023 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110011200120023 - 210 = 110011200118999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011200170023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005600060011 + 55005600060012.
It is an arithmetic number, because the mean of its divisors is an integer number (55005600060012).
Almost surely, 2110011200120023 is an apocalyptic number.
110011200120023 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011200120023 is an equidigital number, since it uses as much as digits as its factorization.
110011200120023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 110011200120023 its reverse (320021002110011), we get a palindrome (430032202230034).
The spelling of 110011200120023 in words is "one hundred ten trillion, eleven billion, two hundred million, one hundred twenty thousand, twenty-three".
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