Base | Representation |
---|---|
bin | 11001000000111000110110… |
… | …110000110111110110111000 |
3 | 112102112001202010212222202020 |
4 | 121000320312300313312320 |
5 | 103404420002020213422 |
6 | 1025550525002034440 |
7 | 32113056101254455 |
oct | 3100706660676670 |
9 | 472461663788666 |
10 | 110012211101112 |
11 | 32064a0a1771a1 |
12 | 1040912aaa8a20 |
13 | 49501510a9088 |
14 | 1d248959d082c |
15 | caba0b78195c |
hex | 640e36c37db8 |
110012211101112 has 32 divisors (see below), whose sum is σ = 284514339056400. Its totient is φ = 35406228859904.
The previous prime is 110012211101101. The next prime is 110012211101159. The reversal of 110012211101112 is 211101112210011.
It is a junction number, because it is equal to n+sod(n) for n = 110012211101091 and 110012211101100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79031760153 + ... + 79031761544.
Almost surely, 2110012211101112 is an apocalyptic number.
110012211101112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110012211101112 is an abundant number, since it is smaller than the sum of its proper divisors (174502127955288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110012211101112 is a wasteful number, since it uses less digits than its factorization.
110012211101112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158063521735 (or 158063521731 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 15.
Adding to 110012211101112 its reverse (211101112210011), we get a palindrome (321113323311123).
The spelling of 110012211101112 in words is "one hundred ten trillion, twelve billion, two hundred eleven million, one hundred one thousand, one hundred twelve".
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