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11001231130000 = 24542694089677
BaseRepresentation
bin1010000000010110110001…
…1110010011110110010000
31102221201002201020120011211
42200011230132103312100
52420221010132130000
635221521254545504
72213545522464526
oct240055436236620
942851081216154
1011001231130000
113561661198121
121298142068294
1361a5474c7947
142a0668c8a316
151412797e37ba
hexa016c793d90

11001231130000 has 100 divisors (see below), whose sum is σ = 26734102395660. Its totient is φ = 4384132672000.

The previous prime is 11001231129953. The next prime is 11001231130013. The reversal of 11001231130000 is 3113210011.

It can be written as a sum of positive squares in 10 ways, for example, as 10995962112256 + 5269017744 = 3316016^2 + 72588^2 .

It is a tau number, because it is divible by the number of its divisors (100).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 645162 + ... + 4734838.

Almost surely, 211001231130000 is an apocalyptic number.

11001231130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11001231130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13367051197830).

11001231130000 is an abundant number, since it is smaller than the sum of its proper divisors (15732871265660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11001231130000 is an equidigital number, since it uses as much as digits as its factorization.

11001231130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4089974 (or 4089953 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11001231130000 its reverse (3113210011), we get a palindrome (11004344340011).

The spelling of 11001231130000 in words is "eleven trillion, one billion, two hundred thirty-one million, one hundred thirty thousand".

Divisors: 1 2 4 5 8 10 16 20 25 40 50 80 100 125 200 250 269 400 500 538 625 1000 1076 1250 1345 2000 2152 2500 2690 4304 5000 5380 6725 10000 10760 13450 21520 26900 33625 53800 67250 107600 134500 168125 269000 336250 538000 672500 1345000 2690000 4089677 8179354 16358708 20448385 32717416 40896770 65434832 81793540 102241925 163587080 204483850 327174160 408967700 511209625 817935400 1022419250 1100123113 1635870800 2044838500 2200246226 2556048125 4089677000 4400492452 5112096250 5500615565 8179354000 8800984904 10224192500 11001231130 17601969808 20448385000 22002462260 27503077825 40896770000 44004924520 55006155650 88009849040 110012311300 137515389125 220024622600 275030778250 440049245200 550061556500 687576945625 1100123113000 1375153891250 2200246226000 2750307782500 5500615565000 11001231130000