Base | Representation |
---|---|
bin | 10100011111011101… |
… | …01010101100110000 |
3 | 1001101200220110012221 |
4 | 22033232222230300 |
5 | 140012313410000 |
6 | 5015352130424 |
7 | 536423410042 |
oct | 121756525460 |
9 | 31350813187 |
10 | 11001310000 |
11 | 4735a5303a |
12 | 2170396a14 |
13 | 10642959b5 |
14 | 765131a92 |
15 | 445c4c61a |
hex | 28fbaab30 |
11001310000 has 50 divisors (see below), whose sum is σ = 26635295852. Its totient is φ = 4400520000.
The previous prime is 11001309997. The next prime is 11001310007. The reversal of 11001310000 is 1310011.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (50).
It is a super-2 number, since 2×110013100002 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11001310007) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 540066 + ... + 560065.
Almost surely, 211001310000 is an apocalyptic number.
11001310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11001310000 is an abundant number, since it is smaller than the sum of its proper divisors (15633985852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11001310000 is an equidigital number, since it uses as much as digits as its factorization.
11001310000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1100159 (or 1100138 counting only the distinct ones).
The product of its (nonzero) digits is 3, while the sum is 7.
Adding to 11001310000 its reverse (1310011), we get a palindrome (11002620011).
The spelling of 11001310000 in words is "eleven billion, one million, three hundred ten thousand".
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