Base | Representation |
---|---|
bin | 10000000000100101000… |
… | …011100100110010101101 |
3 | 10220011122011221012222221 |
4 | 100000211003210302231 |
5 | 121011033112300101 |
6 | 2201221055035341 |
7 | 142324220642065 |
oct | 20004503446255 |
9 | 3804564835887 |
10 | 1100133321901 |
11 | 394622641789 |
12 | 15926850bb51 |
13 | 7c9855b7a83 |
14 | 3b3650903a5 |
15 | 1d93c538aa1 |
hex | 100250e4cad |
1100133321901 has 2 divisors, whose sum is σ = 1100133321902. Its totient is φ = 1100133321900.
The previous prime is 1100133321899. The next prime is 1100133321919. The reversal of 1100133321901 is 1091233310011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1094858786025 + 5274535876 = 1046355^2 + 72626^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100133321901 - 21 = 1100133321899 is a prime.
Together with 1100133321899, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100133321941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550066660950 + 550066660951.
It is an arithmetic number, because the mean of its divisors is an integer number (550066660951).
Almost surely, 21100133321901 is an apocalyptic number.
It is an amenable number.
1100133321901 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100133321901 is an equidigital number, since it uses as much as digits as its factorization.
1100133321901 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
Adding to 1100133321901 its reverse (1091233310011), we get a palindrome (2191366631912).
The spelling of 1100133321901 in words is "one trillion, one hundred billion, one hundred thirty-three million, three hundred twenty-one thousand, nine hundred one".
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