Base | Representation |
---|---|
bin | 10000000000100101110… |
… | …011110111000100110111 |
3 | 10220011200001202022020102 |
4 | 100000211303313010313 |
5 | 121011044332322303 |
6 | 2201222230224315 |
7 | 142324433351231 |
oct | 20004563670467 |
9 | 3804601668212 |
10 | 1100145979703 |
11 | 3946297a7781 |
12 | 1592707b509b |
13 | 7c9880ca2b4 |
14 | 3b366a27251 |
15 | 1d93d6d9288 |
hex | 10025cf7137 |
1100145979703 has 2 divisors, whose sum is σ = 1100145979704. Its totient is φ = 1100145979702.
The previous prime is 1100145979661. The next prime is 1100145979717. The reversal of 1100145979703 is 3079795410011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100145979703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100145979733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550072989851 + 550072989852.
It is an arithmetic number, because the mean of its divisors is an integer number (550072989852).
Almost surely, 21100145979703 is an apocalyptic number.
1100145979703 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100145979703 is an equidigital number, since it uses as much as digits as its factorization.
1100145979703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 238140, while the sum is 47.
The spelling of 1100145979703 in words is "one trillion, one hundred billion, one hundred forty-five million, nine hundred seventy-nine thousand, seven hundred three".
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