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11003141034 = 2331919953891
BaseRepresentation
bin10100011111101011…
…01001101110101010
31001101211100110221000
422033311221232222
5140013301003114
65015455255430
7536445104244
oct121765515652
931354313830
1011003141034
114736a93796
122170b1a576
131064787252
1476548b094
15445eaee09
hex28fd69baa

11003141034 has 64 divisors (see below), whose sum is σ = 25868160000. Its totient is φ = 3457151280.

The previous prime is 11003141027. The next prime is 11003141041. The reversal of 11003141034 is 43014130011.

It is an interprime number because it is at equal distance from previous prime (11003141027) and next prime (11003141041).

It is a super-3 number, since 3×110031410343 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11003140998 and 11003141016.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 177229 + ... + 231119.

It is an arithmetic number, because the mean of its divisors is an integer number (404190000).

Almost surely, 211003141034 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11003141034, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12934080000).

11003141034 is an abundant number, since it is smaller than the sum of its proper divisors (14865018966).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11003141034 is a wasteful number, since it uses less digits than its factorization.

11003141034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54120 (or 54114 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11003141034 its reverse (43014130011), we get a palindrome (54017271045).

The spelling of 11003141034 in words is "eleven billion, three million, one hundred forty-one thousand, thirty-four".

Divisors: 1 2 3 6 9 18 19 27 38 54 57 114 171 199 342 398 513 597 1026 1194 1791 3582 3781 5373 7562 10746 11343 22686 34029 53891 68058 102087 107782 161673 204174 323346 485019 970038 1023929 1455057 2047858 2910114 3071787 6143574 9215361 10724309 18430722 21448618 27646083 32172927 55292166 64345854 96518781 193037562 203761871 289556343 407523742 579112686 611285613 1222571226 1833856839 3667713678 5501570517 11003141034