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110031421421400 = 233521741263107177
BaseRepresentation
bin11001000001001010101111…
…110010011011011101011000
3112102120220022221111101002020
4121001022233302123131120
5103410223322340441100
61030003423121534440
732114336124300243
oct3101125762333530
9472526287441066
10110031421421400
1132072077974156
12104109b04a4420
134951bc2ca53bb
141d2579907625a
15cac2830135a0
hex6412afc9b758

110031421421400 has 192 divisors, whose sum is σ = 369970789416480. Its totient is φ = 26942174822400.

The previous prime is 110031421421387. The next prime is 110031421421419. The reversal of 110031421421400 is 4124124130011.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 131135389 + ... + 131971788.

Almost surely, 2110031421421400 is an apocalyptic number.

110031421421400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

110031421421400 is an abundant number, since it is smaller than the sum of its proper divisors (259939367995080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110031421421400 is a wasteful number, since it uses less digits than its factorization.

110031421421400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 263107254 (or 263107245 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 110031421421400 its reverse (4124124130011), we get a palindrome (114155545551411).

The spelling of 110031421421400 in words is "one hundred ten trillion, thirty-one billion, four hundred twenty-one million, four hundred twenty-one thousand, four hundred".