Base | Representation |
---|---|
bin | 10100011111101100… |
… | …11000000111101001 |
3 | 1001101211201010120121 |
4 | 22033312120013221 |
5 | 140013323043144 |
6 | 5015503323241 |
7 | 536446525234 |
oct | 121766300751 |
9 | 31354633517 |
10 | 11003331049 |
11 | 4737103527 |
12 | 2170bb0521 |
13 | 1064822899 |
14 | 7654da41b |
15 | 445eeb384 |
hex | 28fd981e9 |
11003331049 has 2 divisors, whose sum is σ = 11003331050. Its totient is φ = 11003331048.
The previous prime is 11003331047. The next prime is 11003331133. The reversal of 11003331049 is 94013330011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6971081049 + 4032250000 = 83493^2 + 63500^2 .
It is a cyclic number.
It is not a de Polignac number, because 11003331049 - 21 = 11003331047 is a prime.
Together with 11003331047, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11003331041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501665524 + 5501665525.
It is an arithmetic number, because the mean of its divisors is an integer number (5501665525).
Almost surely, 211003331049 is an apocalyptic number.
It is an amenable number.
11003331049 is a deficient number, since it is larger than the sum of its proper divisors (1).
11003331049 is an equidigital number, since it uses as much as digits as its factorization.
11003331049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 11003331049 in words is "eleven billion, three million, three hundred thirty-one thousand, forty-nine".
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