Base | Representation |
---|---|
bin | 11001000001001101010101… |
… | …100101110100100001001110 |
3 | 112102121011111210210000102221 |
4 | 121001031111211310201032 |
5 | 103410300022000242110 |
6 | 1030005003131405554 |
7 | 32114465062411510 |
oct | 3101152545644116 |
9 | 472534453700387 |
10 | 110034203134030 |
11 | 320732750a100a |
12 | 10411447bb38ba |
13 | 495224739b8c6 |
14 | 1d25980699bb0 |
15 | cac3973397da |
hex | 64135597484e |
110034203134030 has 64 divisors (see below), whose sum is σ = 229547846218752. Its totient is φ = 37194067572480.
The previous prime is 110034203134019. The next prime is 110034203134061. The reversal of 110034203134030 is 30431302430011.
It is a junction number, because it is equal to n+sod(n) for n = 110034203133986 and 110034203134004.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 405749442 + ... + 406020538.
It is an arithmetic number, because the mean of its divisors is an integer number (3586685097168).
Almost surely, 2110034203134030 is an apocalyptic number.
110034203134030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
110034203134030 is an abundant number, since it is smaller than the sum of its proper divisors (119513643084722).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110034203134030 is a wasteful number, since it uses less digits than its factorization.
110034203134030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 352849.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 110034203134030 its reverse (30431302430011), we get a palindrome (140465505564041).
The spelling of 110034203134030 in words is "one hundred ten trillion, thirty-four billion, two hundred three million, one hundred thirty-four thousand, thirty".
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