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11006634344591 is a prime number
BaseRepresentation
bin1010000000101010111010…
…0001111100000010001111
31102222020001021100022011202
42200022232201330002033
52420313041343011331
635224213352340115
72214126442162664
oct240125641740217
942866037308152
1011006634344591
113563984166226
1212991ab6a463b
1361abc8a52042
142a0a1c70ba6b
15141493d45ecb
hexa02ae87c08f

11006634344591 has 2 divisors, whose sum is σ = 11006634344592. Its totient is φ = 11006634344590.

The previous prime is 11006634344561. The next prime is 11006634344593. The reversal of 11006634344591 is 19544343660011.

It is a strong prime.

It is an emirp because it is prime and its reverse (19544343660011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11006634344591 - 210 = 11006634343567 is a prime.

It is a super-2 number, since 2×110066343445912 (a number of 27 digits) contains 22 as substring.

Together with 11006634344593, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11006634344593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503317172295 + 5503317172296.

It is an arithmetic number, because the mean of its divisors is an integer number (5503317172296).

Almost surely, 211006634344591 is an apocalyptic number.

11006634344591 is a deficient number, since it is larger than the sum of its proper divisors (1).

11006634344591 is an equidigital number, since it uses as much as digits as its factorization.

11006634344591 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 933120, while the sum is 47.

The spelling of 11006634344591 in words is "eleven trillion, six billion, six hundred thirty-four million, three hundred forty-four thousand, five hundred ninety-one".