11010011009983 has 2 divisors, whose sum is σ = 11010011009984. Its totient is φ = 11010011009982.

The previous prime is 11010011009981. The next prime is 11010011009993. The reversal of 11010011009983 is 38990011001011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11010011009983 - 2¹ = 11010011009981 is a prime.

It is a super-3 number, since 3×11010011009983³ (a number of 40 digits) contains 333 as substring.

Together with 11010011009981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010011009981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505005504991 + 5505005504992.

It is an arithmetic number, because the mean of its divisors is an integer number (5505005504992).

Almost surely, 2^{11010011009983} is an apocalyptic number.

11010011009983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010011009983 is an equidigital number, since it uses as much as digits as its factorization.

11010011009983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 34.

The spelling of 11010011009983 in words is "eleven trillion, ten billion, eleven million, nine thousand, nine hundred eighty-three".