Base | Representation |
---|---|
bin | 1010000000110111111001… |
… | …1010110000000000000111 |
3 | 1102222120001100012201021001 |
4 | 2200031332122300000013 |
5 | 2420342212230334343 |
6 | 35225551423434131 |
7 | 2214312042612661 |
oct | 240157632600007 |
9 | 42876040181231 |
10 | 11010122121223 |
11 | 35654039a4455 |
12 | 1299a03755947 |
13 | 61b3334cbab4 |
14 | 2a0c6da07531 |
15 | 1415ea13b44d |
hex | a037e6b0007 |
11010122121223 has 2 divisors, whose sum is σ = 11010122121224. Its totient is φ = 11010122121222.
The previous prime is 11010122121221. The next prime is 11010122121241. The reversal of 11010122121223 is 32212122101011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11010122121223 - 21 = 11010122121221 is a prime.
Together with 11010122121221, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 11010122121223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11010122121221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505061060611 + 5505061060612.
It is an arithmetic number, because the mean of its divisors is an integer number (5505061060612).
Almost surely, 211010122121223 is an apocalyptic number.
11010122121223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010122121223 is an equidigital number, since it uses as much as digits as its factorization.
11010122121223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11010122121223 its reverse (32212122101011), we get a palindrome (43222244222234).
The spelling of 11010122121223 in words is "eleven trillion, ten billion, one hundred twenty-two million, one hundred twenty-one thousand, two hundred twenty-three".
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