Search a number
-
+
11011314200 = 235255056571
BaseRepresentation
bin10100100000101001…
…10101001000011000
31001102101201201101212
422100110311020120
5140022344023300
65020350402252
7536604424565
oct122024651030
931371651355
1011011314200
114740666377
122173800388
131066389443
147665b786c
15446a76935
hex290535218

11011314200 has 24 divisors (see below), whose sum is σ = 25601305980. Its totient is φ = 4404525600.

The previous prime is 11011314157. The next prime is 11011314217. The reversal of 11011314200 is 241311011.

It is a super-3 number, since 3×110113142003 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 27528086 + ... + 27528485.

Almost surely, 211011314200 is an apocalyptic number.

11011314200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11011314200 is an abundant number, since it is smaller than the sum of its proper divisors (14589991780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11011314200 is a wasteful number, since it uses less digits than its factorization.

11011314200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55056587 (or 55056578 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11011314200 its reverse (241311011), we get a palindrome (11252625211).

The spelling of 11011314200 in words is "eleven billion, eleven million, three hundred fourteen thousand, two hundred".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 200 55056571 110113142 220226284 275282855 440452568 550565710 1101131420 1376414275 2202262840 2752828550 5505657100 11011314200