1101407 has 2 divisors, whose sum is σ = 1101408. Its totient is φ = 1101406.

The previous prime is 1101403. The next prime is 1101409. The reversal of 1101407 is 7041011.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (7041011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101407 - 2² = 1101403 is a prime.

Together with 1101409, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1101391 and 1101400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550703 + 550704.

It is an arithmetic number, because the mean of its divisors is an integer number (550704).

2^1101407 is an apocalyptic number.

1101407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101407 is an equidigital number, since it uses as much as digits as its factorization.

1101407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 1101407 is about 1049.4793947477. The cubic root of 1101407 is about 103.2720054639.

Adding to 1101407 its reverse (7041011), we get a palindrome (8142418).

The spelling of 1101407 in words is "one million, one hundred one thousand, four hundred seven".