Base | Representation |
---|---|
bin | 11001000011111010011000… |
… | …110011101101110111000010 |
3 | 112110020221010022112120021002 |
4 | 121003322120303231313002 |
5 | 103421321042144201340 |
6 | 1030230213044532002 |
7 | 32134063464446264 |
oct | 3103723063556702 |
9 | 473227108476232 |
10 | 110220014443970 |
11 | 321350557a6382 |
12 | 104414639b1002 |
13 | 4966919c84792 |
14 | 1d3096a1c7b34 |
15 | cb211ed07715 |
hex | 643e98ceddc2 |
110220014443970 has 32 divisors (see below), whose sum is σ = 210075505004016. Its totient is φ = 41492791296000.
The previous prime is 110220014443969. The next prime is 110220014444039. The reversal of 110220014443970 is 79344410022011.
110220014443970 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 8 ways, for example, as 60262104059689 + 49957910384281 = 7762867^2 + 7068091^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10152581 + ... + 17986520.
Almost surely, 2110220014443970 is an apocalyptic number.
110220014443970 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
110220014443970 is a deficient number, since it is larger than the sum of its proper divisors (99855490560046).
110220014443970 is a wasteful number, since it uses less digits than its factorization.
110220014443970 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28162166.
The product of its (nonzero) digits is 48384, while the sum is 38.
Adding to 110220014443970 its reverse (79344410022011), we get a palindrome (189564424465981).
The spelling of 110220014443970 in words is "one hundred ten trillion, two hundred twenty billion, fourteen million, four hundred forty-three thousand, nine hundred seventy".
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