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1102242351317 is a prime number
BaseRepresentation
bin10000000010100010110…
…000111000100011010101
310220101002011110000110112
4100002202300320203111
5121024343020220232
62202210234532405
7142430410253642
oct20024260704325
93811064400415
101102242351317
113955050877a8
12159756897105
137cc30517783
143b4c520adc9
151da127864b2
hex100a2c388d5

1102242351317 has 2 divisors, whose sum is σ = 1102242351318. Its totient is φ = 1102242351316.

The previous prime is 1102242351269. The next prime is 1102242351319. The reversal of 1102242351317 is 7131532422011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1088017972561 + 14224378756 = 1043081^2 + 119266^2 .

It is a cyclic number.

It is not a de Polignac number, because 1102242351317 - 238 = 827364444373 is a prime.

Together with 1102242351319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1102242351319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551121175658 + 551121175659.

It is an arithmetic number, because the mean of its divisors is an integer number (551121175659).

Almost surely, 21102242351317 is an apocalyptic number.

It is an amenable number.

1102242351317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102242351317 is an equidigital number, since it uses as much as digits as its factorization.

1102242351317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

Adding to 1102242351317 its reverse (7131532422011), we get a palindrome (8233774773328).

The spelling of 1102242351317 in words is "one trillion, one hundred two billion, two hundred forty-two million, three hundred fifty-one thousand, three hundred seventeen".