110231400401 has 2 divisors, whose sum is σ = 110231400402. Its totient is φ = 110231400400.

The previous prime is 110231400397. The next prime is 110231400403. The reversal of 110231400401 is 104004132011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109180019776 + 1051380625 = 330424^2 + 32425^2 .

It is a cyclic number.

It is not a de Polignac number, because 110231400401 - 2² = 110231400397 is a prime.

Together with 110231400403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110231400401.

It is not a weakly prime, because it can be changed into another prime (110231400403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55115700200 + 55115700201.

It is an arithmetic number, because the mean of its divisors is an integer number (55115700201).

Almost surely, 2^110231400401 is an apocalyptic number.

It is an amenable number.

110231400401 is a deficient number, since it is larger than the sum of its proper divisors (1).

110231400401 is an equidigital number, since it uses as much as digits as its factorization.

110231400401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 110231400401 its reverse (104004132011), we get a palindrome (214235532412).

The spelling of 110231400401 in words is "one hundred ten billion, two hundred thirty-one million, four hundred thousand, four hundred one".