Base | Representation |
---|---|
bin | 10100100010111000… |
… | …00111111100001111 |
3 | 1001110200220020021002 |
4 | 22101130013330033 |
5 | 140042140102341 |
6 | 5022255130515 |
7 | 540222324344 |
oct | 122134077417 |
9 | 31420806232 |
10 | 11030003471 |
11 | 4750170953 |
12 | 2179b13a3b |
13 | 106a201096 |
14 | 768c807cb |
15 | 44851929b |
hex | 291707f0f |
11030003471 has 2 divisors, whose sum is σ = 11030003472. Its totient is φ = 11030003470.
The previous prime is 11030003423. The next prime is 11030003473. The reversal of 11030003471 is 17430003011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11030003471 is a prime.
It is a super-3 number, since 3×110300034713 (a number of 31 digits) contains 333 as substring.
Together with 11030003473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11030003473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515001735 + 5515001736.
It is an arithmetic number, because the mean of its divisors is an integer number (5515001736).
Almost surely, 211030003471 is an apocalyptic number.
11030003471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11030003471 is an equidigital number, since it uses as much as digits as its factorization.
11030003471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 11030003471 its reverse (17430003011), we get a palindrome (28460006482).
The spelling of 11030003471 in words is "eleven billion, thirty million, three thousand, four hundred seventy-one".
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