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11038395971231 is a prime number
BaseRepresentation
bin1010000010100001001110…
…1010111011011010011111
31110002021000210110002222222
42200220103222323122133
52421323113332034411
635250545154255555
72216332512434366
oct240502352733237
943067023402888
1011038395971231
1135763a2834442
1212a33945875bb
13620bbb08cb65
142a2392ac07dd
151422024484db
hexa0a13abb69f

11038395971231 has 2 divisors, whose sum is σ = 11038395971232. Its totient is φ = 11038395971230.

The previous prime is 11038395971219. The next prime is 11038395971233. The reversal of 11038395971231 is 13217959383011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11038395971231 - 222 = 11038391776927 is a prime.

It is a super-3 number, since 3×110383959712313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 11038395971233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11038395971233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5519197985615 + 5519197985616.

It is an arithmetic number, because the mean of its divisors is an integer number (5519197985616).

Almost surely, 211038395971231 is an apocalyptic number.

11038395971231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11038395971231 is an equidigital number, since it uses as much as digits as its factorization.

11038395971231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 53.

The spelling of 11038395971231 in words is "eleven trillion, thirty-eight billion, three hundred ninety-five million, nine hundred seventy-one thousand, two hundred thirty-one".