Base | Representation |
---|---|
bin | 1010000011011100100101… |
… | …1111001000100000000110 |
3 | 1110010210011100110100102211 |
4 | 2200313021133020200012 |
5 | 2422103232243444220 |
6 | 35302142322254034 |
7 | 2220435430101340 |
oct | 240671137104006 |
9 | 43123140410384 |
10 | 11054331234310 |
11 | 358212a883451 |
12 | 12a64a11b731a |
13 | 62255a5cb000 |
14 | 2a3065200290 |
15 | 142836402b5a |
hex | a0dc97c8806 |
11054331234310 has 64 divisors (see below), whose sum is σ = 24634504540800. Its totient is φ = 3498513572736.
The previous prime is 11054331234299. The next prime is 11054331234329. The reversal of 11054331234310 is 1343213345011.
It is a super-2 number, since 2×110543312343102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35785905 + ... + 36093484.
It is an arithmetic number, because the mean of its divisors is an integer number (384914133450).
Almost surely, 211054331234310 is an apocalyptic number.
11054331234310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11054331234310 is an abundant number, since it is smaller than the sum of its proper divisors (13580173306490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11054331234310 is an equidigital number, since it uses as much as digits as its factorization.
11054331234310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71879442 (or 71879416 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 11054331234310 its reverse (1343213345011), we get a palindrome (12397544579321).
The spelling of 11054331234310 in words is "eleven trillion, fifty-four billion, three hundred thirty-one million, two hundred thirty-four thousand, three hundred ten".
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