1110000000047 has 2 divisors, whose sum is σ = 1110000000048. Its totient is φ = 1110000000046.

The previous prime is 1110000000023. The next prime is 1110000000049. The reversal of 1110000000047 is 7400000000111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1110000000047 - 2⁸ = 1109999999791 is a prime.

Together with 1110000000049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1109999999959 and 1110000000040.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110000000049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555000000023 + 555000000024.

It is an arithmetic number, because the mean of its divisors is an integer number (555000000024).

Almost surely, 2^{1110000000047} is an apocalyptic number.

1110000000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110000000047 is an equidigital number, since it uses as much as digits as its factorization.

1110000000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 1110000000047 its reverse (7400000000111), we get a palindrome (8510000000158).

The spelling of 1110000000047 in words is "one trillion, one hundred ten billion, forty-seven", and thus it is an aban number.