Base | Representation |
---|---|
bin | 1010000110000111001000… |
… | …0111101110100100000111 |
3 | 1110022011022202111202110221 |
4 | 2201201302013232210013 |
5 | 2423331011142334343 |
6 | 35335153054525211 |
7 | 2223646035160054 |
oct | 241416207564407 |
9 | 43264282452427 |
10 | 11100110121223 |
11 | 359a591869792 |
12 | 12b3338506807 |
13 | 6269749ac086 |
14 | 2a53690a002b |
15 | 143b153e75ed |
hex | a18721ee907 |
11100110121223 has 2 divisors, whose sum is σ = 11100110121224. Its totient is φ = 11100110121222.
The previous prime is 11100110121181. The next prime is 11100110121257. The reversal of 11100110121223 is 32212101100111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11100110121223 - 237 = 10962671167751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11100110121197 and 11100110121206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100110124223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055060611 + 5550055060612.
It is an arithmetic number, because the mean of its divisors is an integer number (5550055060612).
Almost surely, 211100110121223 is an apocalyptic number.
11100110121223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100110121223 is an equidigital number, since it uses as much as digits as its factorization.
11100110121223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 11100110121223 its reverse (32212101100111), we get a palindrome (43312211221334).
The spelling of 11100110121223 in words is "eleven trillion, one hundred billion, one hundred ten million, one hundred twenty-one thousand, two hundred twenty-three".
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