Base | Representation |
---|---|
bin | 1010000110000111011110… |
… | …0110101001000010010111 |
3 | 1110022011120011121022220102 |
4 | 2201201313212221002113 |
5 | 2423331203220024002 |
6 | 35335210142324315 |
7 | 2223651233111153 |
oct | 241416746510227 |
9 | 43264504538812 |
10 | 11100202111127 |
11 | 359a62978a0a8 |
12 | 12b336328969b |
13 | 62698aa7997c |
14 | 2a53773a8063 |
15 | 143b1d518a02 |
hex | a18779a9097 |
11100202111127 has 2 divisors, whose sum is σ = 11100202111128. Its totient is φ = 11100202111126.
The previous prime is 11100202111121. The next prime is 11100202111129. The reversal of 11100202111127 is 72111120200111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11100202111127 - 24 = 11100202111111 is a prime.
Together with 11100202111129, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11100202111099 and 11100202111108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100202111121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550101055563 + 5550101055564.
It is an arithmetic number, because the mean of its divisors is an integer number (5550101055564).
Almost surely, 211100202111127 is an apocalyptic number.
11100202111127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100202111127 is an equidigital number, since it uses as much as digits as its factorization.
11100202111127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 11100202111127 its reverse (72111120200111), we get a palindrome (83211322311238).
The spelling of 11100202111127 in words is "eleven trillion, one hundred billion, two hundred two million, one hundred eleven thousand, one hundred twenty-seven".
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