Base | Representation |
---|---|
bin | 110011101100001000… |
… | …0100100010010101101 |
3 | 101121111221121101011122 |
4 | 1213120100210102231 |
5 | 3304313103412023 |
6 | 122554354430325 |
7 | 11006512603064 |
oct | 1473020442255 |
9 | 347457541148 |
10 | 111002404013 |
11 | 43091a66086 |
12 | 1961a5923a5 |
13 | a610099387 |
14 | 55303991db |
15 | 2d4a1012c8 |
hex | 19d84244ad |
111002404013 has 2 divisors, whose sum is σ = 111002404014. Its totient is φ = 111002404012.
The previous prime is 111002403961. The next prime is 111002404027. The reversal of 111002404013 is 310404200111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86146359049 + 24856044964 = 293507^2 + 157658^2 .
It is a cyclic number.
It is not a de Polignac number, because 111002404013 - 26 = 111002403949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111002403982 and 111002404000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111002404613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501202006 + 55501202007.
It is an arithmetic number, because the mean of its divisors is an integer number (55501202007).
Almost surely, 2111002404013 is an apocalyptic number.
It is an amenable number.
111002404013 is a deficient number, since it is larger than the sum of its proper divisors (1).
111002404013 is an equidigital number, since it uses as much as digits as its factorization.
111002404013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 111002404013 its reverse (310404200111), we get a palindrome (421406604124).
The spelling of 111002404013 in words is "one hundred eleven billion, two million, four hundred four thousand, thirteen".
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