111013212031333 has 2 divisors, whose sum is σ = 111013212031334. Its totient is φ = 111013212031332.

The previous prime is 111013212031327. The next prime is 111013212031343. The reversal of 111013212031333 is 333130212310111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84421677768129 + 26591534263204 = 9188127^2 + 5156698^2 .

It is a cyclic number.

It is not a de Polignac number, because 111013212031333 - 2²¹ = 111013209934181 is a prime.

It is a super-3 number, since 3×111013212031333³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111013212031298 and 111013212031307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111013212031343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506606015666 + 55506606015667.

It is an arithmetic number, because the mean of its divisors is an integer number (55506606015667).

Almost surely, 2^{111013212031333} is an apocalyptic number.

It is an amenable number.

111013212031333 is a deficient number, since it is larger than the sum of its proper divisors (1).

111013212031333 is an equidigital number, since it uses as much as digits as its factorization.

111013212031333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 111013212031333 its reverse (333130212310111), we get a palindrome (444143424341444).

The spelling of 111013212031333 in words is "one hundred eleven trillion, thirteen billion, two hundred twelve million, thirty-one thousand, three hundred thirty-three".