111100130000 has 100 divisors (see below), whose sum is σ = 270062277408. Its totient is φ = 44262000000.

The previous prime is 111100129981. The next prime is 111100130021. The reversal of 111100130000 is 31001111.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a self number, because there is not a number n which added to its sum of digits gives 111100130000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 2487869 + ... + 2532131.

Almost surely, 2^111100130000 is an apocalyptic number.

111100130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111100130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (135031138704).

111100130000 is an abundant number, since it is smaller than the sum of its proper divisors (158962147408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111100130000 is an equidigital number, since it uses as much as digits as its factorization.

111100130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44542 (or 44521 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 111100130000 its reverse (31001111), we get a palindrome (111131131111).

The spelling of 111100130000 in words is "one hundred eleven billion, one hundred million, one hundred thirty thousand".