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11111000120093 is a prime number
BaseRepresentation
bin1010000110101111101100…
…1101110001101100011101
31110100012102200222000112102
42201223323031301230131
52424020312012320333
635344153433214445
72224512640504646
oct241537315615435
943305380860472
1011111000120093
1135a416a9a5055
1212b5477561425
136279bbba09a3
142a5abd4d86cd
151440514a8ae8
hexa1afb371b1d

11111000120093 has 2 divisors, whose sum is σ = 11111000120094. Its totient is φ = 11111000120092.

The previous prime is 11111000120071. The next prime is 11111000120113. The reversal of 11111000120093 is 39002100011111.

It is a happy number.

It is an a-pointer prime, because the next prime (11111000120113) can be obtained adding 11111000120093 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8357083103044 + 2753917017049 = 2890862^2 + 1659493^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111000120093 - 226 = 11110933011229 is a prime.

It is a super-3 number, since 3×111110001200933 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111000120293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500060046 + 5555500060047.

It is an arithmetic number, because the mean of its divisors is an integer number (5555500060047).

Almost surely, 211111000120093 is an apocalyptic number.

It is an amenable number.

11111000120093 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111000120093 is an equidigital number, since it uses as much as digits as its factorization.

11111000120093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 20.

The spelling of 11111000120093 in words is "eleven trillion, one hundred eleven billion, one hundred twenty thousand, ninety-three".