Base | Representation |
---|---|
bin | 110011101111011001… |
… | …1011100011011001111 |
3 | 101121210121020002211202 |
4 | 1213132303130123033 |
5 | 3310024211211002 |
6 | 123013320140115 |
7 | 11012315126402 |
oct | 1473663343317 |
9 | 347717202752 |
10 | 111112210127 |
11 | 43138a45036 |
12 | 1964b30763b |
13 | a629a643c9 |
14 | 5540bbdd39 |
15 | 2d54a91502 |
hex | 19decdc6cf |
111112210127 has 2 divisors, whose sum is σ = 111112210128. Its totient is φ = 111112210126.
The previous prime is 111112210091. The next prime is 111112210129. The reversal of 111112210127 is 721012211111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111112210127 - 212 = 111112206031 is a prime.
It is a super-2 number, since 2×1111122101272 (a number of 23 digits) contains 22 as substring.
Together with 111112210129, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 111112210099 and 111112210108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111112210129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556105063 + 55556105064.
It is an arithmetic number, because the mean of its divisors is an integer number (55556105064).
Almost surely, 2111112210127 is an apocalyptic number.
111112210127 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112210127 is an equidigital number, since it uses as much as digits as its factorization.
111112210127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 111112210127 its reverse (721012211111), we get a palindrome (832124421238).
The spelling of 111112210127 in words is "one hundred eleven billion, one hundred twelve million, two hundred ten thousand, one hundred twenty-seven".
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