Base | Representation |
---|---|
bin | 1010000110110000110110… |
… | …1101000001110001011100 |
3 | 1110100020020022121220112022 |
4 | 2201230031231001301130 |
5 | 2424021430414133200 |
6 | 35344244313355312 |
7 | 2224523425143155 |
oct | 241541555016134 |
9 | 43306208556468 |
10 | 11111310302300 |
11 | 35a4309aa358a |
12 | 12b5543408b38 |
13 | 627a3b225260 |
14 | 2a5b0c79c92c |
15 | 14406d829885 |
hex | a1b0db41c5c |
11111310302300 has 72 divisors (see below), whose sum is σ = 26044726437072. Its totient is φ = 4090242816000.
The previous prime is 11111310302233. The next prime is 11111310302311. The reversal of 11111310302300 is 320301311111.
It is a super-2 number, since 2×111113103023002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12480821 + ... + 13341420.
It is an arithmetic number, because the mean of its divisors is an integer number (361732311626).
Almost surely, 211111310302300 is an apocalyptic number.
11111310302300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11111310302300 is an abundant number, since it is smaller than the sum of its proper divisors (14933416134772).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11111310302300 is a wasteful number, since it uses less digits than its factorization.
11111310302300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25822599 (or 25822592 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11111310302300 its reverse (320301311111), we get a palindrome (11431611613411).
The spelling of 11111310302300 in words is "eleven trillion, one hundred eleven billion, three hundred ten million, three hundred two thousand, three hundred".
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