11111323320133 has 2 divisors, whose sum is σ = 11111323320134. Its totient is φ = 11111323320132.

The previous prime is 11111323320113. The next prime is 11111323320179. The reversal of 11111323320133 is 33102332311111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11049820312129 + 61503008004 = 3324127^2 + 247998^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111323320133 - 2³⁷ = 10973884366661 is a prime.

It is a super-3 number, since 3×11111323320133³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11111323320098 and 11111323320107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111323320113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555661660066 + 5555661660067.

It is an arithmetic number, because the mean of its divisors is an integer number (5555661660067).

Almost surely, 2^{11111323320133} is an apocalyptic number.

It is an amenable number.

11111323320133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111323320133 is an equidigital number, since it uses as much as digits as its factorization.

11111323320133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11111323320133 its reverse (33102332311111), we get a palindrome (44213655631244).

The spelling of 11111323320133 in words is "eleven trillion, one hundred eleven billion, three hundred twenty-three million, three hundred twenty thousand, one hundred thirty-three".