Base | Representation |
---|---|
bin | 10000001010110101001… |
… | …010111101110100100100 |
3 | 10221020001100000221210011 |
4 | 100022311022331310210 |
5 | 121201104111104444 |
6 | 2210241242140004 |
7 | 143164053424630 |
oct | 20126512756444 |
9 | 3836040027704 |
10 | 1111141113124 |
11 | 3992612111a9 |
12 | 15b41aab1604 |
13 | 80a1b00c7c3 |
14 | 3bacadcbdc0 |
15 | 1dd83b16734 |
hex | 102b52bdd24 |
1111141113124 has 24 divisors (see below), whose sum is σ = 2258713085888. Its totient is φ = 468396721440.
The previous prime is 1111141113109. The next prime is 1111141113169. The reversal of 1111141113124 is 4213111411111.
It is a junction number, because it is equal to n+sod(n) for n = 1111141113095 and 1111141113104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 325273794 + ... + 325277209.
Almost surely, 21111141113124 is an apocalyptic number.
1111141113124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1111141113124 is an abundant number, since it is smaller than the sum of its proper divisors (1147571972764).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1111141113124 is a wasteful number, since it uses less digits than its factorization.
1111141113124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 650551075 (or 650551073 counting only the distinct ones).
The product of its digits is 96, while the sum is 22.
Adding to 1111141113124 its reverse (4213111411111), we get a palindrome (5324252524235).
The spelling of 1111141113124 in words is "one trillion, one hundred eleven billion, one hundred forty-one million, one hundred thirteen thousand, one hundred twenty-four".
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