Search a number
-
+
111120020022012 = 22361151803306041
BaseRepresentation
bin11001010001000000100101…
…010100100010001011111100
3112120102222012020211001010120
4121101000211110202023330
5104031042300111201022
61032155455451534540
732256104453601321
oct3121004524421374
9476388166731116
10111120020022012
1132451810456021
1210567979a5a450
134a0075a9447b1
141d62348222b48
15cca747a86d5c
hex6510255222fc

111120020022012 has 24 divisors (see below), whose sum is σ = 263530539288912. Its totient is φ = 36432793449600.

The previous prime is 111120020021957. The next prime is 111120020022071. The reversal of 111120020022012 is 210220020021111.

111120020022012 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 111120020021982 and 111120020022000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75901652289 + ... + 75901653752.

It is an arithmetic number, because the mean of its divisors is an integer number (10980439137038).

Almost surely, 2111120020022012 is an apocalyptic number.

111120020022012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

111120020022012 is an abundant number, since it is smaller than the sum of its proper divisors (152410519266900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111120020022012 is a wasteful number, since it uses less digits than its factorization.

111120020022012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151803306109 (or 151803306107 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 111120020022012 its reverse (210220020021111), we get a palindrome (321340040043123).

Subtracting 111120020022012 from its reverse (210220020021111), we obtain a palindrome (99099999999099).

The spelling of 111120020022012 in words is "one hundred eleven trillion, one hundred twenty billion, twenty million, twenty-two thousand, twelve".

Divisors: 1 2 3 4 6 12 61 122 183 244 366 732 151803306041 303606612082 455409918123 607213224164 910819836246 1821639672492 9260001668501 18520003337002 27780005005503 37040006674004 55560010011006 111120020022012