Base | Representation |
---|---|
bin | 11001010001000000100101… |
… | …010100100010001011111100 |
3 | 112120102222012020211001010120 |
4 | 121101000211110202023330 |
5 | 104031042300111201022 |
6 | 1032155455451534540 |
7 | 32256104453601321 |
oct | 3121004524421374 |
9 | 476388166731116 |
10 | 111120020022012 |
11 | 32451810456021 |
12 | 10567979a5a450 |
13 | 4a0075a9447b1 |
14 | 1d62348222b48 |
15 | cca747a86d5c |
hex | 6510255222fc |
111120020022012 has 24 divisors (see below), whose sum is σ = 263530539288912. Its totient is φ = 36432793449600.
The previous prime is 111120020021957. The next prime is 111120020022071. The reversal of 111120020022012 is 210220020021111.
111120020022012 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 111120020021982 and 111120020022000.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75901652289 + ... + 75901653752.
It is an arithmetic number, because the mean of its divisors is an integer number (10980439137038).
Almost surely, 2111120020022012 is an apocalyptic number.
111120020022012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
111120020022012 is an abundant number, since it is smaller than the sum of its proper divisors (152410519266900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111120020022012 is a wasteful number, since it uses less digits than its factorization.
111120020022012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151803306109 (or 151803306107 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 111120020022012 its reverse (210220020021111), we get a palindrome (321340040043123).
Subtracting 111120020022012 from its reverse (210220020021111), we obtain a palindrome (99099999999099).
The spelling of 111120020022012 in words is "one hundred eleven trillion, one hundred twenty billion, twenty million, twenty-two thousand, twelve".
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