1111311201300 has 72 divisors (see below), whose sum is σ = 3240711914496. Its totient is φ = 294016181760.

The previous prime is 1111311201289. The next prime is 1111311201359. The reversal of 1111311201300 is 31021131111.

It is a super-2 number, since 2×1111311201300² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1111311201300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14546037 + ... + 14622236.

Almost surely, 2^{1111311201300} is an apocalyptic number.

1111311201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1111311201300 is an abundant number, since it is smaller than the sum of its proper divisors (2129400713196).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1111311201300 is a wasteful number, since it uses less digits than its factorization.

1111311201300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29168417 (or 29168410 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 1111311201300 its reverse (31021131111), we get a palindrome (1142332332411).

The spelling of 1111311201300 in words is "one trillion, one hundred eleven billion, three hundred eleven million, two hundred one thousand, three hundred".