Base | Representation |
---|---|
bin | 1010000111010001111110… |
… | …1101101111010101011100 |
3 | 1110101002012000200221210121 |
4 | 2201310133231233111130 |
5 | 2424143133304212104 |
6 | 35352314522244324 |
7 | 2225256660634300 |
oct | 241643755572534 |
9 | 43332160627717 |
10 | 11120202413404 |
11 | 35a80623a5237 |
12 | 12b72053566a4 |
13 | 62882752c066 |
14 | 2a631372bd00 |
15 | 1443de2e4254 |
hex | a1d1fb6f55c |
11120202413404 has 144 divisors (see below), whose sum is σ = 23561924198400. Its totient is φ = 4573899792000.
The previous prime is 11120202413371. The next prime is 11120202413431. The reversal of 11120202413404 is 40431420202111.
It is a super-3 number, since 3×111202024134043 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 384116322 + ... + 384145270.
It is an arithmetic number, because the mean of its divisors is an integer number (163624473600).
Almost surely, 211120202413404 is an apocalyptic number.
11120202413404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11120202413404, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (11780962099200).
11120202413404 is an abundant number, since it is smaller than the sum of its proper divisors (12441721784996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11120202413404 is a wasteful number, since it uses less digits than its factorization.
11120202413404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29520 (or 29511 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11120202413404 its reverse (40431420202111), we get a palindrome (51551622615515).
The spelling of 11120202413404 in words is "eleven trillion, one hundred twenty billion, two hundred two million, four hundred thirteen thousand, four hundred four".
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