Base | Representation |
---|---|
bin | 1010000111010101010111… |
… | …1000001001100110101110 |
3 | 1110101011112100120122002020 |
4 | 2201311111320021212232 |
5 | 2424202013421041420 |
6 | 35352545023011010 |
7 | 2225321333512536 |
oct | 241652570114656 |
9 | 43334470518066 |
10 | 11121111112110 |
11 | 35a8489328aaa |
12 | 12b7419739a66 |
13 | 62894087cbbc |
14 | 2a639c2b04c6 |
15 | 144443e8d340 |
hex | a1d55e099ae |
11121111112110 has 16 divisors (see below), whose sum is σ = 26690666669136. Its totient is φ = 2965629629888.
The previous prime is 11121111112087. The next prime is 11121111112123. The reversal of 11121111112110 is 1121111112111.
It is a happy number.
11121111112110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×111211111121104 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 11121111112110.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185351851839 + ... + 185351851898.
It is an arithmetic number, because the mean of its divisors is an integer number (1668166666821).
Almost surely, 211121111112110 is an apocalyptic number.
11121111112110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11121111112110 is an abundant number, since it is smaller than the sum of its proper divisors (15569555557026).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11121111112110 is a wasteful number, since it uses less digits than its factorization.
11121111112110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370703703747.
The product of its (nonzero) digits is 4, while the sum is 15.
Adding to 11121111112110 its reverse (1121111112111), we get a palindrome (12242222224221).
Subtracting from 11121111112110 its reverse (1121111112111), we obtain a palindrome (9999999999999).
The spelling of 11121111112110 in words is "eleven trillion, one hundred twenty-one billion, one hundred eleven million, one hundred twelve thousand, one hundred ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •