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111213225133 is a prime number
BaseRepresentation
bin110011110010011010…
…0110010010010101101
3101122001122022012101021
41213210310302102231
53310231041201013
6123031325214141
711014652546653
oct1474464622255
9348048265337
10111213225133
114318aa6a10a
1219679101351
13a644971bba
145550396dd3
152d5d896a8d
hex19e4d324ad

111213225133 has 2 divisors, whose sum is σ = 111213225134. Its totient is φ = 111213225132.

The previous prime is 111213225131. The next prime is 111213225197. The reversal of 111213225133 is 331522312111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68679112489 + 42534112644 = 262067^2 + 206238^2 .

It is a cyclic number.

It is not a de Polignac number, because 111213225133 - 21 = 111213225131 is a prime.

Together with 111213225131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 111213225098 and 111213225107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111213225131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606612566 + 55606612567.

It is an arithmetic number, because the mean of its divisors is an integer number (55606612567).

Almost surely, 2111213225133 is an apocalyptic number.

It is an amenable number.

111213225133 is a deficient number, since it is larger than the sum of its proper divisors (1).

111213225133 is an equidigital number, since it uses as much as digits as its factorization.

111213225133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1080, while the sum is 25.

Adding to 111213225133 its reverse (331522312111), we get a palindrome (442735537244).

The spelling of 111213225133 in words is "one hundred eleven billion, two hundred thirteen million, two hundred twenty-five thousand, one hundred thirty-three".