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111213313220032 = 261737708019063
BaseRepresentation
bin11001010010010111011110…
…000001110101110111000000
3112120202220000000102112122221
4121102113132001311313000
5104034104331141020112
61032310405112540424
732265616401650302
oct3122273601656700
9476686000375587
10111213313220032
1132488334a95571
1210581a756b1714
134a094a7b0704a
141d66a78649972
15cccda80c0e07
hex6525de075dc0

111213313220032 has 14 divisors (see below), whose sum is σ = 220688918421128. Its totient is φ = 55606656609984.

The previous prime is 111213313219997. The next prime is 111213313220069. The reversal of 111213313220032 is 230022313312111.

It is a junction number, because it is equal to n+sod(n) for n = 111213313219979 and 111213313220006.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 868854009468 + ... + 868854009595.

Almost surely, 2111213313220032 is an apocalyptic number.

It is an amenable number.

111213313220032 is a deficient number, since it is larger than the sum of its proper divisors (109475605201096).

111213313220032 is an equidigital number, since it uses as much as digits as its factorization.

111213313220032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1737708019075 (or 1737708019065 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 111213313220032 its reverse (230022313312111), we get a palindrome (341235626532143).

The spelling of 111213313220032 in words is "one hundred eleven trillion, two hundred thirteen billion, three hundred thirteen million, two hundred twenty thousand, thirty-two".

Divisors: 1 2 4 8 16 32 64 1737708019063 3475416038126 6950832076252 13901664152504 27803328305008 55606656610016 111213313220032