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111221301020983 is a prime number
BaseRepresentation
bin11001010010011110111010…
…001000111000100100110111
3112120210122121200212212121121
4121102132322020320210313
5104034222211030132413
61032314205455124411
732266321344101566
oct3122367210704467
9476718550785547
10111221301020983
113249076399065a
1210583524813707
134a0a17b96869a
141d671d5459bdd
15ccd1c44abb8d
hex6527ba238937

111221301020983 has 2 divisors, whose sum is σ = 111221301020984. Its totient is φ = 111221301020982.

The previous prime is 111221301020981. The next prime is 111221301021029. The reversal of 111221301020983 is 389020103122111.

It is a weak prime.

It is an emirp because it is prime and its reverse (389020103122111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111221301020983 - 21 = 111221301020981 is a prime.

It is a super-2 number, since 2×1112213010209832 (a number of 29 digits) contains 22 as substring.

Together with 111221301020981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111221301020981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55610650510491 + 55610650510492.

It is an arithmetic number, because the mean of its divisors is an integer number (55610650510492).

Almost surely, 2111221301020983 is an apocalyptic number.

111221301020983 is a deficient number, since it is larger than the sum of its proper divisors (1).

111221301020983 is an equidigital number, since it uses as much as digits as its factorization.

111221301020983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 34.

The spelling of 111221301020983 in words is "one hundred eleven trillion, two hundred twenty-one billion, three hundred one million, twenty thousand, nine hundred eighty-three".