Base | Representation |
---|---|
bin | 10100101101111101… |
… | …11011001011000101 |
3 | 1001201011220120101021 |
4 | 22112332323023011 |
5 | 140234442343133 |
6 | 5035420431141 |
7 | 542432021161 |
oct | 122676731305 |
9 | 31634816337 |
10 | 11123012293 |
11 | 4798717848 |
12 | 21a50a84b1 |
13 | 10835676a3 |
14 | 777371ca1 |
15 | 45178c52d |
hex | 296fbb2c5 |
11123012293 has 2 divisors, whose sum is σ = 11123012294. Its totient is φ = 11123012292.
The previous prime is 11123012291. The next prime is 11123012311. The reversal of 11123012293 is 39221032111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11073984289 + 49028004 = 105233^2 + 7002^2 .
It is an emirp because it is prime and its reverse (39221032111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11123012293 - 21 = 11123012291 is a prime.
Together with 11123012291, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11123012291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561506146 + 5561506147.
It is an arithmetic number, because the mean of its divisors is an integer number (5561506147).
Almost surely, 211123012293 is an apocalyptic number.
It is an amenable number.
11123012293 is a deficient number, since it is larger than the sum of its proper divisors (1).
11123012293 is an equidigital number, since it uses as much as digits as its factorization.
11123012293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 11123012293 in words is "eleven billion, one hundred twenty-three million, twelve thousand, two hundred ninety-three".
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