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11123312001719 is a prime number
BaseRepresentation
bin1010000111011101100100…
…0011111000001010110111
31110101101012201221102001012
42201313121003320022313
52424221020333023334
635353551243422435
72225430016665401
oct241673103701267
943341181842035
1011123312001719
1135a9408705a35
1212b7932824a1b
13628c01833448
142a652a6ddb71
151445222d39ce
hexa1dd90f82b7

11123312001719 has 2 divisors, whose sum is σ = 11123312001720. Its totient is φ = 11123312001718.

The previous prime is 11123312001677. The next prime is 11123312001721. The reversal of 11123312001719 is 91710021332111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11123312001719 - 228 = 11123043566263 is a prime.

It is a super-2 number, since 2×111233120017192 (a number of 27 digits) contains 22 as substring.

Together with 11123312001721, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11123312001799) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561656000859 + 5561656000860.

It is an arithmetic number, because the mean of its divisors is an integer number (5561656000860).

Almost surely, 211123312001719 is an apocalyptic number.

11123312001719 is a deficient number, since it is larger than the sum of its proper divisors (1).

11123312001719 is an equidigital number, since it uses as much as digits as its factorization.

11123312001719 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 32.

The spelling of 11123312001719 in words is "eleven trillion, one hundred twenty-three billion, three hundred twelve million, one thousand, seven hundred nineteen".